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如果用户可能退出，则不发送相关请求

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liuwei
2025-05-15 14:57:26 +08:00
parent 81781833c4
commit d1dca68ffb
1 changed files with 3 additions and 4 deletions
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7
robot.py
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@@ -218,6 +218,9 @@ class Robot(Job):
data = await self.ipad_bot.sync_message()
except Exception as e:
self.LOG.warning(f"获取新消息失败 {e}")
if e == "用户可能退出":
self.LOG.error(f"获取新消息失败 {e},请重启应用重新登录！")
self.ipad_running = False
await asyncio.sleep(5)
continue
@@ -312,10 +315,8 @@ class Robot(Job):
else:
self.LOG.warning("心跳失败")
self.LOG.error(f"wechat_ipad heartbeat heartbeat twice_auto_auth ")
self.login_twice_auto_auth()
except Exception as e:
self.LOG.error(f"wechat_ipad heartbeat: {e}")
self.login_twice_auto_auth()
await asyncio.sleep(5)
async def _heartbeat_task_long(self):
@@ -329,10 +330,8 @@ class Robot(Job):
else:
self.LOG.warning("长连接心跳失败")
self.LOG.error(f"wechat_ipad heartbeat long twice_auto_auth ")
self.login_twice_auto_auth()
except Exception as e:
self.LOG.error(f"wechat_ipad heartbeat long: {e}")
self.login_twice_auto_auth()
await asyncio.sleep(30)
async def _process_ipad_message(self, message: WxMessage):