73 lines
2.4 KiB
Python
73 lines
2.4 KiB
Python
import schedule
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import time
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import sqlite3
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from datetime import datetime, timedelta
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import redis
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# 连接到Redis
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r = redis.Redis(host='192.168.2.32', port=6379, db=0)
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def write_to_db():
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# 连接到SQLite数据库
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conn = sqlite3.connect('message_stats.db')
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c = conn.cursor()
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# 创建表（如果不存在）
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c.execute('''CREATE TABLE IF NOT EXISTS speech_counts (
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group_id TEXT,
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wx_id TEXT,
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date TEXT,
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count INTEGER,
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PRIMARY KEY (group_id, wx_id, date)
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)''')
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# 获取当前日期的前一天
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yesterday = (datetime.now() - timedelta(days=1)).strftime('%Y-%m-%d')
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# 遍历Redis中所有与昨天日期相关的key，并写入数据库
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for key in r.keys(f"*:*:{yesterday}:count"):
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parts = key.decode('utf-8').split(':')
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group_id, wx_id, _date = parts[0], parts[1], parts[2] # _date应该是yesterday，但这里为了完整性还是保留
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count = int(r.hget(key, 'count')) if isinstance(r.hget(key, 'count'), bytes) else 0 # 处理可能的None或空值情况
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# 插入或更新数据库记录
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c.execute("INSERT OR REPLACE INTO speech_counts (group_id, wx_id, date, count) VALUES (?, ?, ?, ?)",
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(group_id, wx_id, yesterday, count))
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conn.commit()
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conn.close()
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def generate_and_send_ranking(groupId,allContacts: dict):
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# 连接到SQLite数据库（假设数据库文件名为database.db）
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conn = sqlite3.connect('database.db')
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cursor = conn.cursor()
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# 编写SQL查询来获取发言数量前20的用户
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query = """
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SELECT group_id,wx_id, COUNT(*) AS speech_count
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FROM speech_counts
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WHERE DATE(date) = DATE('now', '-1 day')
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AND group_id = ?
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GROUP BY group_id,wx_id
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ORDER BY count DESC
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LIMIT 20
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"""
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# 执行查询并获取结果
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cursor.execute(query,(groupId,))
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results = cursor.fetchall()
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# 格式化输出字符串
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ranking_str = "发言数量前20的用户排名:\n"
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for rank, (username, speech_count) in enumerate(results, start=1):
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ranking_str += f"{rank}. {allContacts[username]}: {speech_count} 次发言\n"
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# 关闭数据库连接
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conn.close()
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# 这里我们没有实际“发送”排名，只是返回字符串
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# 如果需要发送，可以在此添加发送逻辑
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return ranking_str
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