消息异常捕获,防止退出循环
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9
robot.py
9
robot.py
@@ -217,7 +217,7 @@ class Robot(Job):
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try:
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data = await self.ipad_bot.sync_message()
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except Exception as e:
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self.LOG.warning(f"获取新消息失败 {e}")
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self.LOG.error(f"获取新消息失败 {e}")
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if e == "用户可能退出":
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self.LOG.error(f"获取新消息失败 {e},请重启应用重新登录!")
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self.ipad_running = False
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@@ -227,6 +227,7 @@ class Robot(Job):
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data = data.get("AddMsgs")
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if data:
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for message in data:
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self.LOG.debug(f"sync_message.处理消息消息内容: {message}")
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# 处理消息
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try:
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wxmsg: WxMessage = WxMessage.from_json(message)
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@@ -237,7 +238,7 @@ class Robot(Job):
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await self._process_ipad_message(wxmsg)
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except Exception as e:
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self.LOG.error(f"捕获消息处理异常,继续进行下一个消息处理{e}")
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continue # 跳过本条消息,继续处理下一条
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continue
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# 使用异步睡眠替代忙等待循环
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await asyncio.sleep(0.5)
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@@ -679,7 +680,7 @@ class Robot(Job):
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except Exception as e:
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self.LOG.error(f"xiu_ren_download_task error:{e}")
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def generate_and_send_ranking(self):
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async def generate_and_send_ranking(self):
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try:
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receivers = self.gbm.get_group_list()
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if not receivers:
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@@ -687,6 +688,6 @@ class Robot(Job):
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for r in receivers:
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if self.gbm.get_group_permission(r, Feature.DAILY_SUMMARY) == PermissionStatus.ENABLED:
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output = self.message_storage.generate_and_send_ranking(r, self.allContacts)
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self.ipad_bot.send_text_message(r, output)
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await self.ipad_bot.send_text_message(r, output)
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except Exception as e:
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self.LOG.error(f"SendRanking error:{e}")
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@@ -3,6 +3,8 @@ from playwright.async_api import async_playwright
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import os
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import asyncio
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# linux 下需要安装字体
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# sudo apt-get install -y fonts-noto-cjk fonts-noto-cjk-extra
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# 将 Markdown 字符串转换为 HTML
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def md_str_to_html(md_content, output_html):
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